Ôn tập chương 1: Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
\(\left(\frac{15}{\sqrt{6}+1}+\frac{4}{\sqrt{6}-2}-\frac{12}{3-\sqrt{6}}\right)\left(\sqrt{6}+11\right)\)
Giải dùm mình phương trình sau với
a)\(\dfrac{5}{4-\sqrt{11}}+\dfrac{1}{3+\sqrt{7}}-\dfrac{6}{\sqrt{7-2}}-\dfrac{\sqrt{7-5}}{2}\) =4+\(\sqrt{11-3\sqrt{7}}\)
b)\(\dfrac{\sqrt{x+\sqrt{y}}}{2\left(\sqrt{x}-\sqrt{y}\right)}-\dfrac{\sqrt{x-\sqrt{y}}}{2\left(\sqrt{x+\sqrt{y}}\right)}-\dfrac{y+x}{y-x}=\dfrac{\sqrt{x}+\sqrt{y}}{\sqrt{x-\sqrt{y}}}\)
Khử mẫu số trong căn thức sau :
a,-4sqrt{frac{sqrt{3}-1}{2+sqrt{3}}}
b,left(m+nright)sqrt{frac{1}{m^2+n^2}}
c,left(m-3right)sqrt{frac{1}{3-m}} (m3)
d,sqrt{11frac{11}{20}},sqrt{13frac{13}{168}},sqrt{7frac{7}{48}}
e,sqrt{frac{x}{2}}+sqrt{frac{2x}{9}}+sqrt{frac{x}{8}}
Đọc tiếp
Khử mẫu số trong căn thức sau :
a,\(-4\sqrt{\frac{\sqrt{3}-1}{2+\sqrt{3}}}\)
b,\(\left(m+n\right)\sqrt{\frac{1}{m^2+n^2}}\)
c,\(\left(m-3\right)\sqrt{\frac{1}{3-m}}\) (m<3)
d,\(\sqrt{11\frac{11}{20}},\sqrt{13\frac{13}{168}},\sqrt{7\frac{7}{48}}\)
e,\(\sqrt{\frac{x}{2}}+\sqrt{\frac{2x}{9}}+\sqrt{\frac{x}{8}}\)
a, \(\dfrac{5}{4-\sqrt{11}}+\dfrac{1}{3+\sqrt{7}}-\dfrac{6}{\sqrt{7}-2}-\dfrac{\sqrt{7}-5}{2}=4+\sqrt{11}-3\sqrt{7}\)
b, \(\dfrac{\sqrt{x}+\sqrt{y}}{2\left(\sqrt{x}-\sqrt{y}\right)}-\dfrac{\sqrt{x}-\sqrt{y}}{2\left(\sqrt{x}+\sqrt{y}\right)}-\dfrac{y+x}{y-x}=\dfrac{\sqrt{x}+\sqrt{y}}{\sqrt{x}-\sqrt{y}}\)
Các bạn giúp mk vs, Mk cần gấp.
rút gọnAleft(sqrt{28}-2sqrt{14}+sqrt{7}right)cdotsqrt{7}+7sqrt{8}Bsqrt{6+2sqrt{5}}-sqrt{6-2sqrt{5}}Cleft(sqrt{7}-sqrt{10}right)^2+sqrt{280}Ddfrac{sqrt{99}}{sqrt{11}}+sqrt{7}cdotsqrt{63}-sqrt{sqrt{81}}Esqrt{27}left(s-sqrt{5}right)^2cdotleft(3sqrt{48}right)giải chi tiết ra giúp mik nha,cảm ơn nhiều
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rút gọn
A=\(\left(\sqrt{28}-2\sqrt{14}+\sqrt{7}\right)\cdot\sqrt{7}+7\sqrt{8}\)
B=\(\sqrt{6+2\sqrt{5}}-\sqrt{6-2\sqrt{5}}\)
C=\(\left(\sqrt{7}-\sqrt{10}\right)^2+\sqrt{280}\)
D=\(\dfrac{\sqrt{99}}{\sqrt{11}}+\sqrt{7}\cdot\sqrt{63}-\sqrt{\sqrt{81}}\)
E=\(\sqrt{27}\left(s-\sqrt{5}\right)^2\cdot\left(3\sqrt{48}\right)\)
giải chi tiết ra giúp mik nha,cảm ơn nhiều
Rút gọn
A=\(\left(\dfrac{15}{\sqrt{6}+1}+\dfrac{4}{\sqrt{6}-2}-\dfrac{12}{3-\sqrt{6}}\right)\left(\sqrt{6}+11\right)\)
Rut gon bieu thuc:
a) (2-\(\sqrt{3}\))\(\sqrt{26+15\sqrt{3}}-\left(2+\sqrt{3}\right)\sqrt{26-15\sqrt{3}}\)
b) \(\frac{1}{\sqrt{3}}+\frac{1}{3\sqrt{2}}+\frac{1}{\sqrt{3}}\sqrt{\frac{5}{12}-\frac{1}{\sqrt{6}}}\)
c) \(\frac{\sqrt{7+\sqrt{5}}+\sqrt{7-\sqrt{5}}}{\sqrt{7+2\sqrt{11}}}-\sqrt{3-2\sqrt{2}}\)
1) Rút gọn:
a) A sqrt{5-2sqrt{3-sqrt{3}}}-sqrt{3+sqrt{3}}+sqrt{2+sqrt{3}}
b) B sqrt{13+sqrt{2}+5sqrt{1+2sqrt{2}}}+sqrt{13+sqrt{2}+5sqrt{1+2sqrt{2}}}
c) C dfrac{sqrt{21+3sqrt{5}}+sqrt{21-3sqrt{5}}}{sqrt{21}+6sqrt{11}}+sqrt{11-6sqrt{2}}
d) D left(sqrt{8+2sqrt{10+2sqrt{5}}}+sqrt{8-2sqrt{10+2sqrt{5}}}right).sqrt{dfrac{2+2sqrt{5}}{2+sqrt{5}}}
e) E dfrac{left(27+10sqrt{2}right)sqrt{27-10sqrt{2}}-left(27-10sqrt{2}right)sqrt{27+10sqrt{2}}}{left(sqrt{sqrt{13}-3}+sqrt{sqrt{13}+3}right):sqrt{sqrt...
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1) Rút gọn:
a) A = \(\sqrt{5-2\sqrt{3-\sqrt{3}}}-\sqrt{3+\sqrt{3}}+\sqrt{2+\sqrt{3}}\)
b) B = \(\sqrt{13+\sqrt{2}+5\sqrt{1+2\sqrt{2}}}+\sqrt{13+\sqrt{2}+5\sqrt{1+2\sqrt{2}}}\)
c) C = \(\dfrac{\sqrt{21+3\sqrt{5}}+\sqrt{21-3\sqrt{5}}}{\sqrt{21}+6\sqrt{11}}+\sqrt{11-6\sqrt{2}}\)
d) D = \(\left(\sqrt{8+2\sqrt{10+2\sqrt{5}}}+\sqrt{8-2\sqrt{10+2\sqrt{5}}}\right).\sqrt{\dfrac{2+2\sqrt{5}}{2+\sqrt{5}}}\)
e) E = \(\dfrac{\left(27+10\sqrt{2}\right)\sqrt{27-10\sqrt{2}}-\left(27-10\sqrt{2}\right)\sqrt{27+10\sqrt{2}}}{\left(\sqrt{\sqrt{13}-3}+\sqrt{\sqrt{13}+3}\right):\sqrt{\sqrt{13}+2}}\)
1 Rút gọn:
a) Afrac{sqrt[]{2+sqrt[]{3}}}{4}+sqrt[]{frac{2-sqrt[]{3}}{16}}+frac{1}{sqrt[]{3}+sqrt[]{2}+1}
b)left(sqrt[]{a+sqrt[]{a^2-8}}right).left(sqrt[]{a-2sqrt[]{2}}-sqrt[]{a+2sqrt[]{2}}right),a2sqrt[]{2}
2.Cho x sqrt[]{2-sqrt[]{3}}.left(sqrt[]{6}+sqrt[]{2}right)-frac{2sqrt[]{6}+sqrt[]{3}}{sqrt[]{8}+1}. Tính A x^5-3x^4-3x^3+6x^2-20x+2022
3. Cho a,b,c 0, frac{a}{a+b}frac{b}{c+a}frac{c}{a+b}. CMR: frac{left(a+bright)^3}{c^3}+frac{left(b+cright)^3}{a^3}+frac{left(a+cright)^3}{b^3}+24
Đọc tiếp
1 Rút gọn:
a) A=\(\frac{\sqrt[]{2+\sqrt[]{3}}}{4}+\sqrt[]{\frac{2-\sqrt[]{3}}{16}}+\frac{1}{\sqrt[]{3}+\sqrt[]{2}+1}\)
b)\(\left(\sqrt[]{a+\sqrt[]{a^2-8}}\right).\left(\sqrt[]{a-2\sqrt[]{2}}-\sqrt[]{a+2\sqrt[]{2}}\right),a>=2\sqrt[]{2}\)
2.Cho x= \(\sqrt[]{2-\sqrt[]{3}}.\left(\sqrt[]{6}+\sqrt[]{2}\right)-\frac{2\sqrt[]{6}+\sqrt[]{3}}{\sqrt[]{8}+1}\). Tính A= \(x^5-3x^4-3x^3+6x^2-20x+2022\)
3. Cho a,b,c >0, \(\frac{a}{a+b}=\frac{b}{c+a}=\frac{c}{a+b}\). CMR: \(\frac{\left(a+b\right)^3}{c^3}+\frac{\left(b+c\right)^3}{a^3}+\frac{\left(a+c\right)^3}{b^3}+24\)