\(n_{AgNO3}=\frac{780.1,09.10\%}{170}=0,5\left(mol\right)\)
\(n_{HCl}=0,16.1,25==0,2\left(mol\right)\)
\(AgNO_{3\left(dư\right)}+HCl\rightarrow AgCl+HNO_3\)
0,2_________0,2___________
\(n_{AgNO3\left(pư\right)}=0,3\left(mol\right)\)
\(KBr+AgNO_3\rightarrow AgBr+KNO_3\)
a_______a___________
\(KI+AgNO_3\rightarrow AgI+KNO_3\)
b_______b____________
\(\Rightarrow\left\{{}\begin{matrix}a+b=0,3\\119a+166b=45,1\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}a=0,1\\b=0,2\end{matrix}\right.\)
\(C\%_{KBr}=\frac{119.0,1.10}{45,1+454,9}=2,38\%\)