\(S=4\left(x^2+\frac{1}{x}+\frac{1}{x}\right)+y^2+\frac{27}{y}+\frac{27}{y}\)
\(S\ge12\sqrt[3]{\frac{x^2}{x^2}}+3\sqrt[3]{\frac{27^2.y^2}{y^2}}=39\)
\(S_{min}=39\) khi \(\left\{{}\begin{matrix}x^2=\frac{1}{x}\\y^2=\frac{27}{y}\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}x=1\\y=3\end{matrix}\right.\) \(\Rightarrow T=5\)