Question

1)(x-2)(x+1)=0
2)(3-x)x=0
3)2x-17=-(3x-18)

Answer 1

1) Ta có: \(\left(x-2\right)\left(x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\)

Vậy \(x=2\) hoặc \(x=-1\)

2) Ta có: \(\left(3-x\right)x=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3-x=0\\x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)

Vậy \(x=3\) hoặc \(x=0\)

3) Ta có: \(2x-17=-\left(3x-18\right)\)

\(\Leftrightarrow2x-17=18-3x\)

\(\Leftrightarrow2x+3x=18+17\)

\(\Leftrightarrow5x=35\Leftrightarrow x=\dfrac{35}{5}=7\)

Vậy \(x=7\)

Answer 2

(1)X1=2 và X2=-2

(2)X1=3 và X2=0

(3) X=7