1. _ \(n_{NaOH\left(dd1\right)}=0,3mol\)
_ \(n_{NaOH\left(dd2\right)}=0,2.1,5=0,3mol\)
_ \(V_{NaOHm}=300+200=500ml=0,5l\)
\(\Rightarrow C_M=\dfrac{0,6}{0,5}=1,2M\)
_ \(m_{NaOHm}=0,6.40=24\left(g\right)\)
\(\Rightarrow m_{ddNaOH}=500.1,05=525\left(g\right)\)
\(\Rightarrow C\%=\dfrac{24}{525}.100\%=4,57\%\)