\(\sqrt{12-2\sqrt{35}}=\sqrt{5-2\sqrt{5}.\sqrt{7}+7}=\sqrt{\left(\sqrt{5}-\sqrt{7}\right)^2}=\left|\sqrt{5}-\sqrt{7}\right|=\sqrt{7}-\sqrt{5}\)
\(\sqrt{12-2\sqrt{35}}=\sqrt{5-2\sqrt{5}.\sqrt{7}+7}=\sqrt{\left(\sqrt{5}-\sqrt{7}\right)^2}=\left|\sqrt{5}-\sqrt{7}\right|=\sqrt{7}-\sqrt{5}\)
a) \(\sqrt{2}+\frac{1}{\sqrt{5+2\sqrt{6}}}+\frac{2}{\sqrt{8+2\sqrt{15}}}\)
b) \(\frac{\sqrt{8}+3}{\sqrt{17-3\sqrt{32}}}+\frac{3+2\sqrt{5}}{\sqrt{29-12\sqrt{5}}}-\frac{1}{\sqrt{12+2\sqrt{35}}}\)
c) \(\left(\frac{15}{3-\sqrt{2}}-\frac{2}{1-\sqrt{3}}+\frac{3}{\sqrt{3}-2}\right):\sqrt{28+10\sqrt{3}}\)
Giúp mình bài này nhé, mình đang cần gấp mọi người ơi :<
Tính
a,\(\sqrt{14-2\sqrt{33}}\)
b,\(\sqrt{12-2\sqrt{35}}\)
c,\(\sqrt{16-2\sqrt{55}}\)
d,\(\sqrt{14-6\sqrt{5}}\)
e,\(\sqrt{17-12\sqrt{2}}\)
\(\)Mn giúp mình vs.. mình đang cần gấp ạ, cảm ơn mn nhiều lắm.. hjx
\(\sqrt{46-6\sqrt{ }5}-\sqrt{29-12\sqrt{ }5}\)
\(\sqrt{7-3\sqrt{ }5}\)
\(\left(3-\sqrt{ }2\right)\sqrt{11+6\sqrt{ }2}\)
\(\sqrt{4+\sqrt{ }15}\)
\(\left(\sqrt{ }5+\sqrt{ }7\right)\sqrt{12-2\sqrt{ }35}\)
\(\sqrt{17-12\sqrt[]{}2}\)
\(\sqrt{14-6\sqrt{ }5}\)
\(\sqrt{27-12\sqrt{ }5}\)
so sánh \(\dfrac{\sqrt{21}-\sqrt{13}}{35-2\sqrt{273}}+\dfrac{\sqrt{10}-\sqrt{5}}{16-10\sqrt{2}}\)với 1
Giải pt :
\(x+\dfrac{x}{\sqrt{x^2-1}}=\dfrac{35}{12}\)
\(A=\left(\dfrac{1}{1-\sqrt{x}}-\dfrac{1}{\sqrt{x}}\right):\left(\dfrac{2x+\sqrt{x}-1}{1-x}+\dfrac{2x\sqrt{x}+x-\sqrt{x}}{1+x\sqrt{x}}\right)\)
a) Rút gọn biểu thức
b) Tính GTBT A khi x = 17 - 12√2
So sánh A=\(\dfrac{1}{\sqrt{1}+\sqrt{2}}+\dfrac{1}{\sqrt{2}+\sqrt{3}}+\dfrac{1}{\sqrt{3}+\sqrt{4}}+...+\dfrac{1}{\sqrt{120}+\sqrt{121}}\)
với B=\(\dfrac{1}{\sqrt{1}}+\dfrac{1}{\sqrt{2}}+\dfrac{1}{\sqrt{3}}+...+\dfrac{1}{\sqrt{35}}\)
11) \(\frac{3}{\sqrt{6}-\sqrt{3}}+\frac{4}{\sqrt{7}+\sqrt{3}}\)
12) \(\frac{6}{3\sqrt{2}+2\sqrt{3}}\)
13) \(\left(\sqrt{75}-3\sqrt{2}-\sqrt{12}\right)\left(\sqrt{3}+\sqrt{2}\right)\)
14)\(\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}+\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}\)
15)\(\frac{\sqrt{5}-\sqrt{3}}{\sqrt{5}+\sqrt{3}}+\frac{\sqrt{5}+\sqrt{3}}{\sqrt{5}-\sqrt{3}}-\frac{\sqrt{5}+1}{\sqrt{5}-1}\)
16)\(\frac{\sqrt{2}}{2\sqrt{3}+4\sqrt{2}}\)
17) \(\frac{1}{4-3\sqrt{2}}-\frac{1}{4+3\sqrt{2}}\)
18)\(\frac{6}{\sqrt{2}-\sqrt{3}+3}\)
19)\(\frac{\sqrt{3+2\sqrt{2}}+\sqrt{3-2\sqrt{2}}}{\sqrt{3+2\sqrt{2}}-\sqrt{3-2\sqrt{2}}}\)
20)\(\sqrt{24}+6\sqrt{\frac{2}{3}}+\frac{10}{\sqrt{6}-1}\)
21)\(2\sqrt{40\sqrt{12}}-2\sqrt{\sqrt{75}}-3\sqrt{5\sqrt{58}}\)
22)\(4\sqrt{20}-3\sqrt{125}+5\sqrt{45}-15\sqrt{\frac{1}{5}}\)
23)\(\left(3\sqrt{8}-2\sqrt{12}+\sqrt{20}\right):\left(3\sqrt{18}-2\sqrt{27}+\sqrt{45}\right)\)
24)\(\left(\frac{15}{\sqrt{6}+1}+\frac{4}{\sqrt{6}-2}-\frac{12}{3-\sqrt{6}}\right)\left(\sqrt{6}+11\right)\)
25)\(\left(\sqrt{7}-\sqrt{5}\right)^2+2\sqrt{35}\)
26)\(\frac{\sqrt{6}+\sqrt{14}}{2\sqrt{3}+\sqrt{28}}+\frac{3\sqrt{45}+\sqrt{243}}{\sqrt{5}+\sqrt{3}}\)
27)\(\frac{1}{\sqrt{7-\sqrt{24}}+1}-\frac{1}{\sqrt{7+\sqrt{24}}-1}\)
28)\(\frac{1}{2+\sqrt{3}}+\frac{1}{\sqrt{3}}-\frac{2}{3+\sqrt{3}}\)
29)\(\frac{3+\sqrt{5}}{2\sqrt{2}+\sqrt{3+\sqrt{5}}}+\frac{3-\sqrt{5}}{2\sqrt{2}-\sqrt{3-\sqrt{5}}}\)
30)\(\left(15\sqrt{50}+5\sqrt{200}-3\sqrt{450}\right):\sqrt{10}\)
31)\(\left(\frac{2}{\sqrt{3}-1}+\frac{3}{\sqrt{3}-2}+\frac{15}{3-\sqrt{3}}\right).\frac{1}{\sqrt{3}+5}\)
32)\(\frac{5+\sqrt{5}}{5-\sqrt{5}}+\frac{5-\sqrt{5}}{5+\sqrt{5}}-\sqrt{10}\)
Thực hiện phép tính: \(\sqrt{12}+2\sqrt{27}+3\sqrt{75}-9\sqrt{48}\)