Question

1.tính:

a) A= \(2^3\).\(5^3-3\).{639-8(\(7^8\):\(7^6\)+1)}

b) B= \(-19^2 \)-{147-2[\(7^3\)+(93-126):(6-\(3^2\))]}

Answer 1

a) A= \(2^3.5^3-3.\left[639-8\left(7^8:7^6+1\right)\right]\)

= \(2^3.5^3-3.\left[639-8.50\right]\)

= \(2^3.5^3-3.\left[639-400\right]\)

= \(2^3.5^3-3.239\)

= \(10^3-717\)

= 283

b) \(-19^2-\left\{147-2\left[7^3+\left(93-126\right):\left(6-3^2\right)\right]\right\}\)

= \(-19^2-\left\{147-2\left[7^3+\left(-33\right):\left(-3\right)\right]\right\}\)

= \(-19^2-\left\{147-2\left[7^3+11\right]\right\}\)

\(=-19^2-\left\{147-2.354\right\}\)

\(=-19^2-\left\{-561\right\}\)

= 922

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