a/
\(\Leftrightarrow\Delta=\left(m+2\right)^2-4\left(-2m+1\right)\le0\)
\(\Leftrightarrow m^2+12m\le0\Rightarrow-12\le m\le0\)
b/ Đặt \(f\left(x\right)=x^2-2mx+m^2-9\)
Để BPT thỏa mãn đề bài
\(\Leftrightarrow\left\{{}\begin{matrix}\Delta>0\\x_1\le-2< 2\le x_2\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}m^2-\left(m^2-9\right)>0\\f\left(-2\right)\le0\\f\left(2\right)\le0\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}9>0\\m^2+4m-5\le0\\m^2-4m-5\le0\end{matrix}\right.\) \(\Leftrightarrow\left\{{}\begin{matrix}-5\le m\le1\\-1\le m\le5\end{matrix}\right.\)
\(\Rightarrow-1\le m\le1\)