Giải hệ pt
\(\left\{{}\begin{matrix}x^3+4y=y^3+16x\\1+y^2=5\left(1+x^2\right)\end{matrix}\right.\)
giải hpt:
\(\left\{{}\begin{matrix}x\left(x+1\right)+\dfrac{1}{y}\left(\dfrac{1}{y}+1\right)=4\\x^3y^3+x^2y^2+xy+1=4y^3\end{matrix}\right.\)
1/ Giải hpt = p đặt ẩn phụ : a,\(\left\{{}\begin{matrix}\left(x+y\right)^3+y=5\\3\left(x+y\right)^3-22xy+21=11x^2+12y^3\end{matrix}\right.\)
b,\(\left\{{}\begin{matrix}81x^3y^2-81x^2y^2+33xy^2-29y^2=4\\25y^3+9x^2y^3-6xy^3-4y^2=24\end{matrix}\right.\)
Giải HPT:
\(\left\{{}\begin{matrix}x^4+2\left(3y+1\right)x^2+\left(5y^2+4y+11\right)x-y^2+10y+2=0\\y^3+\left(x-2\right)y+x^2+x+2=0\end{matrix}\right.\)
Giải các hpt:
1)\(\left\{{}\begin{matrix}\frac{10}{x-1}+\frac{1}{y+2}=1\\\frac{25}{x-1}+\frac{3}{y+2}=2\end{matrix}\right.\)
2)\(\left\{{}\begin{matrix}4\left|x+y\right|-3\left|x-y\right|=8\\3\left|x+y\right|-5\left|x-y\right|=6\end{matrix}\right.\)
Giải pt và hpt :
1. \(\left(x-3\right)\sqrt{10-x^2}=x^2-x-12\)
2. \(\begin{cases}x+3y=1\\x^2+y^2-3y=1\end{cases}\)
3. \(\begin{cases}y^2=\left(5x+4\right)\left(4-x\right)\\y^2-5x^2-4xy+16x-8y+16=0\end{cases}\)
giải hpt:
\(\left\{{}\begin{matrix}3\left(y^2+x^2\right)+\dfrac{1}{\left(x-y\right)^2}=2\left(10-xy\right)\\2x+\dfrac{1}{x-y}=5\end{matrix}\right.\)
\(\left\{{}\begin{matrix}\left(x-1\right).6+\left(y-2\right).\left(-2\right)=0\\\left(x+1\right).4+\left(y-1\right).\left(-3\right)=0\end{matrix}\right.\)
Giải hpt
1.Giải hpt : a,\(\left\{{}\begin{matrix}\left(x+y+3\right)\sqrt{x-2y}+2y+4=0\\\left(x-y\right)\left(x^2+4\right)=y^2+1\end{matrix}\right.\)