\(A=1\dfrac{1}{15}.1\dfrac{1}{16}.1\dfrac{1}{17}......1\dfrac{1}{2016}.1\dfrac{1}{2017}\)
\(A=\dfrac{16}{15}.\dfrac{17}{16}.\dfrac{18}{17}......\dfrac{2017}{2016}.\dfrac{2018}{2017}\)
\(A=\dfrac{16.17.18......2017.2018}{15.16.17......2016.2017}\)
\(A=\dfrac{2018}{15}\)
Tìm x :\(\dfrac{ }{ }\)\(\dfrac{1}{2}\)x -\(\dfrac{3}{4}\)=\(\dfrac{1}{3}\)x +\(1\dfrac{2}{5}\)
Tìm số nguyên \(x\):
a, \(\left(\dfrac{1}{12}+3\dfrac{1}{6}-30,75\right).x-8=\left(\dfrac{3}{5}+0,415\right)\)
b, \(4\dfrac{1}{3}.\left(\dfrac{1}{6}-\dfrac{1}{2}\right)\le x\le\dfrac{2}{3}.\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)
x-\(\dfrac{20}{11.13}-\dfrac{20}{13.15}-\dfrac{20}{15.17}-...-\dfrac{20}{53.55}=\dfrac{3}{11}\)
A=\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+...+\dfrac{1}{99.100}\)
\(\dfrac{-2}{3}\left|x\right|+1\dfrac{1}{2}=\dfrac{2}{5}\)
CÁC BẠN ƠI,GIÚP MÌNH VỚI,MÌNH SẮP THI RỒI,HUHU
Bài 1:tìm x,biết:
a)(\(\dfrac{2x}{5}\)-2):(-5)=\(\dfrac{3}{7}\)
b)x+20%x=-4,8
c)x-15%x=-\(2\dfrac{11}{20}\)
d)\(\dfrac{x+5}{95}\)+\(\dfrac{x+10}{90}\)+\(\dfrac{x+15}{85}\)+\(\dfrac{x+20}{80}\)=-4
Bài 2:So sánh:
A=\(\dfrac{10^{100}+1}{10^{101}+1}\) và B=\(\dfrac{10^{101}+1}{10^{102}+1}\)
Tìm x biết:\(\left(12\dfrac{7}{8}-10\dfrac{13}{18}\right):x-1\dfrac{7}{33}:\dfrac{8}{11}=1\dfrac{2}{3}\)
Tìm \(x\), biết :
a) \(0,5x-\dfrac{2}{3}x=\dfrac{7}{12}\) b) \(x:4\dfrac{1}{3}=-2,5\)
c) \(5,5x=\dfrac{13}{15}\) d) \(\left(\dfrac{3x}{7}+1\right):\left(-4\right)=\dfrac{-1}{28}\)
1, tìm a,b thuộc Z biết : a) \(\dfrac{a}{5}+\dfrac{1}{10}=-\dfrac{1}{b}\)
b) \(\dfrac{a}{9}-\dfrac{3}{b}=\dfrac{1}{18}\)
b, tìm x để \(A=\dfrac{5x}{3}:\dfrac{10x^2+5x}{21}\) là số nguyên .
\(x\dfrac{1}{3}+2x\dfrac{3}{6}-3x\dfrac{4}{9}vớix=\dfrac{2011}{2012}\)
1) (4\(\dfrac{5}{57}\) - 3\(\dfrac{4}{51}\) + 8\(\dfrac{13}{29}\) ) - ( 3\(\dfrac{5}{57}\) - 6\(\dfrac{16}{29}\) )
2) \(\dfrac{6}{7}\) + \(\dfrac{5}{8}\) : 5 - \(\dfrac{3}{16}\) . (-2)\(^2\)
3) 1\(\dfrac{13}{15}\) . 0, 75 - ( \(\dfrac{104}{195}\) + 25% ) . \(^{\dfrac{24}{47}}\) - 3\(\dfrac{12}{13}\) :3
4) [ 80% : \(\dfrac{1}{2}\) - 2 . 0, 75 + (-3)\(^2\) . \(\dfrac{1}{6}\) ] : \(\dfrac{1}{10}\) + 1\(\dfrac{1}{5}\) . ( \(\dfrac{1}{3}\) - \(\dfrac{1}{2}\) )
