Question

(1+3/4-1/4) . (4/3 -3/4)^2

Answer 1

\(\left(1+\frac{3}{4}-\frac{1}{4}\right).\left(\frac{4}{3}-\frac{3}{4}\right)^2=\frac{3}{2}.\left(\frac{7}{12}\right)^2=\frac{3}{2}.\frac{49}{144}=\frac{49}{96}\)

Answer 2

\(\left(1+\frac{3}{4}-\frac{1}{4}\right)\left(\frac{4}{3}-\frac{3}{4}\right)^2=\frac{3}{2}.\left(\frac{7}{12}\right)^2=\frac{3.7^2}{2.2^4.3^2}=\frac{3.7^2}{2^5.3^2}\)

=\(\frac{7^2}{3.2^5}\)

Answer 3

Ta có: \(\left(1+\frac{3}{4}-\frac{1}{4}\right).\left(\frac{4}{3}-\frac{3}{4}\right)^2\)

\(=\left(\frac{4}{4}+\frac{3}{4}-\frac{1}{4}\right).\left(\frac{16}{12}-\frac{9}{12}\right)^2\)

\(=\frac{3}{2}.\left(\frac{7}{12}\right)^2\)

\(=\frac{3}{2}.\frac{49}{144}\)

\(=\frac{49}{96}\)

Chuk bn hk tốt!