Bài 13:
a) Ta có: \(x+\left(-35\right)=18\)
\(\Leftrightarrow x-35=18\)
hay x=18+35=53
Vậy: x=53
b) Ta có: \(-2x-\left(-17\right)=15\)
\(\Leftrightarrow-2x=15+\left(-17\right)=-2\)
hay x=1
Vậy: x=1
a) x + (-35)= 18
<=> x=18+35=53
b) -2x - (-17) = 15
<=> -2x=-2
=> x=1