\(n_{CO_2}=0,1\left(mol\right)\\ PTHH:CaCO_3\underrightarrow{t^o}CaO+CO_2\\ \rightarrow m_{CaO}=56.0,1=5,6\left(g\right)\\ Theo\cdot pt:H=\frac{n_{TT}}{n_{LT}}.100\%\Leftrightarrow n_{TT}=\frac{H.n_{LT}}{100}=\frac{H.0,1}{100}=H.10^{-3}\left(mol\right)\\ \rightarrow m_{CaCO_3TT}=a=H.10^{-3}.100=0,1.H\left(g\right)\)