\(A=\dfrac{\left(12.8\right)^3.5}{2^9.15^2}=\dfrac{\left(2^2.3.2^3\right)^3.5}{2^9.\left(3.5\right)^2}=\dfrac{2^6.3^3.2^9.5}{2^9.3^2.5^2}=\dfrac{2^{15}.3^3.5}{2^9.3^2.5^2}=\dfrac{2^6.3.1}{1.1.5}=\dfrac{192}{5}\)
\(A=\dfrac{\left(12.8\right)^3.5}{2^9.15^2}=\dfrac{\left(2^2.3.2^3\right)^3.5}{2^9.\left(3.5\right)^2}=\dfrac{2^6.3^3.2^9.5}{2^9.3^2.5^2}=\dfrac{2^{15}.3^3.5}{2^9.3^2.5^2}=\dfrac{2^6.3.1}{1.1.5}=\dfrac{192}{5}\)
A=\(\dfrac{\left(12.8\right)^3.5}{2^9.15^2}\)
Thực hiện phép tính: \(\dfrac{20^3.\left(-49\right)^2}{14^3.5^4}\)
\(\left\{\left[\left(2\sqrt{2}\right)^2:2,4\right]X\left[5,25:\left(\sqrt{7}\right)^2\right]\right\}\) : \(\left\{\left[2\dfrac{1}{7}:\dfrac{\left(\sqrt{5}\right)^2}{7}\right]:\left[2^2:\dfrac{\left(2\sqrt{2}\right)^2}{\sqrt{81}}\right]\right\}\)
b, tìm x, y, z thoả mãn đẳng thức
\(\sqrt{\left(x-\sqrt{2}\right)^2}\) + \(\sqrt{\left(y+\sqrt{2}\right)^2}\) + |x + y + z| = 0
tính hợp lý
a, A = \(\dfrac{1-\dfrac{1}{\sqrt{49}}+\dfrac{1}{49}-\dfrac{1}{\left(7\sqrt{7}\right)^2}}{\dfrac{\sqrt{64}}{2}-\dfrac{4}{7}+\left(\dfrac{2}{7}\right)^2-\dfrac{4}{343}}\)
b, M = 1 - \(\dfrac{5}{\sqrt{196}}\) - \(\dfrac{5}{\left(2\sqrt{21}\right)^2}\) - \(\dfrac{\sqrt{25}}{204}\) - \(\dfrac{\left(\sqrt{5}\right)^2}{374}\)
BT1: Tính nhanh:
3) \(\left(\dfrac{1}{3}-\dfrac{1}{4}\right)^2+\left(\dfrac{1}{2}-\dfrac{1}{6}\right)^2+1\dfrac{1}{3}\)
1) Tìm a, b > 0
Sao cho \(\dfrac{1}{a}-\dfrac{1}{b}=\dfrac{1}{a-b}\)
2) Tính nhanh:
\(-4\dfrac{1}{3}\left(\dfrac{1}{2}-\dfrac{1}{6}\right)\le x\le\dfrac{-2}{3}\left(\dfrac{1}{3}-\dfrac{1}{2}-\dfrac{3}{4}\right)\)
Cho 3 số hữu tỉ dương a;b;c thỏa mãn: \(\dfrac{a+b-2c}{c}=\dfrac{b+c-2a}{a}=\dfrac{c+a-2b}{b}\)
Tính giá trị biểu thức: P = \(\left(1+\dfrac{a}{b}\right)\left(2+\dfrac{b^2}{c^2}\right)\left(3+\dfrac{c^3}{a^3}\right)\)
Tinh nhanh
a, A= 0,25+\(\dfrac{3}{5}-\left(\dfrac{1}{8}-\dfrac{2}{5}+2\dfrac{1}{4}\right)\)
Tính nhanh :
\(A=\left(-\dfrac{5}{7}+\dfrac{8}{5}\right):\dfrac{91}{8}+\left(-\dfrac{2}{7}-\dfrac{3}{5}\right):\dfrac{91}{8}\)
\(B=\dfrac{13}{15}:\left(\dfrac{4}{5}-\dfrac{3}{7}\right)+\dfrac{13}{15}:\left(\dfrac{2}{5}-\dfrac{1}{9}\right)\)
(Gíup mình với )