Question

1. Tính

a) \(\dfrac{2}{3}\)-4.(\(\dfrac{1}{2}\)+\(\dfrac{3}{4}\))

b) \(\dfrac{-2}{3}\).\(\dfrac{3}{11}\)+\(\dfrac{-16}{9}\).\(\dfrac{3}{11}\)

c) \(\dfrac{11}{125}\)-\(\dfrac{17}{18}\)-\(\dfrac{5}{7}\)+\(\dfrac{4}{9}\)+\(\dfrac{17}{14}\)

Giúp mình với

Answer 1

a, \(\dfrac{2}{3}-4\left(\dfrac{1}{2}+\dfrac{3}{4}\right)=\dfrac{2}{3}-4.\dfrac{5}{4}=\dfrac{2}{3}-5=-\dfrac{13}{3}\)

b, \(-\dfrac{2}{3}.\dfrac{3}{11}+\dfrac{-16}{9}.\dfrac{3}{11}=\dfrac{3}{11}.\left(-\dfrac{2}{3}+\dfrac{-16}{9}\right)\)

\(=\dfrac{3}{11}.\dfrac{-22}{9}=-\dfrac{2}{3}\)

Câu c lấy máy tính tính nha!

c,

Answer 2

c) \(\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{5}{7}+\dfrac{4}{9}+\dfrac{17}{14}\)

\(=\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{10}{14}+\dfrac{8}{18}+\dfrac{17}{14}\)

\(=\dfrac{11}{125}+\left(-\dfrac{17}{18}+\dfrac{8}{18}\right)+\left(-\dfrac{10}{14}+\dfrac{17}{14}\right)\)

\(=\dfrac{11}{125}+\left(-\dfrac{9}{18}\right)+\dfrac{7}{14}\)

\(=\dfrac{11}{125}+\left(-\dfrac{1}{2}\right)+\dfrac{1}{2}\)

\(=\dfrac{11}{125}+0=\dfrac{11}{125}\)