a) Để \(\dfrac{26}{x+3}\in N\) => \(26⋮\left(x+3\right)\) Hay \(\left(x+3\right)\inƯ\left(26\right)=\left\{1;2;13;26\right\}\)
Ta có bảng :
| x+3 | 1 | 2 | 13 | 26 |
| x | -2 | -1 | 10 | 23 |
Tìm các số tự nhiên x, y sao cho:
a) \(\dfrac{x}{3}-\dfrac{4}{y}=\dfrac{1}{5}\)
b) \(\dfrac{5}{x}-\dfrac{y}{3}=\dfrac{1}{6}\)
c) \(\dfrac{x}{6}-\dfrac{2}{y}=\dfrac{1}{3}\)
tìm x
a\(\dfrac{5x-3}{3-2x}=\dfrac{2}{3}\)
b\(\left(\dfrac{4}{5}x+\dfrac{2}{3}\right)\div\dfrac{3}{4}=2\)
c\(\dfrac{3}{4}x-\dfrac{1}{3}=\dfrac{3}{5}\)
d\(\dfrac{2}{3}-\dfrac{3}{5}\div x=\dfrac{1}{4}\)
giúp mình nhé
Tìm x
a) \(\left|1-x\right|=\dfrac{1}{4}\)
b) \(\dfrac{x+1}{3}=\dfrac{x}{2}\)
c) \(\dfrac{2x}{3}-\dfrac{x}{4}=\dfrac{5}{6}\)
BT: Tìm x, biết:
a) \(2\dfrac{2}{3}x+3\dfrac{3}{4}x=\dfrac{385}{24}\)
b) \(-2\dfrac{2}{3}:x=1\dfrac{7}{9}:0.8\)
c) \(140\%+\dfrac{5}{3}x+2x=2280\)
d) \(-3\dfrac{1}{3}\cdot\left|x\right|=1\dfrac{1}{2}-2\dfrac{2}{3}\)
tìm các số nguyên x và y sao cho
a,\(\dfrac{4}{x}+\dfrac{y}{3}=\dfrac{5}{6}\) b, \(\dfrac{5}{x}-\dfrac{y}{3}=\dfrac{1}{6}\) c, \(\dfrac{x}{6}-\dfrac{2}{y}=\dfrac{1}{30}\)
a)x=\(\dfrac{1}{4}+\dfrac{2}{13}\)
b)\(\dfrac{x}{3}=\dfrac{2}{3}+\dfrac{-1}{7}\)
c)\(\dfrac{-8}{3}+\dfrac{-1}{3}\le x\le\dfrac{-2}{7}+\dfrac{-5}{7}\)
d)\(\dfrac{-5}{6}+\dfrac{8}{3}\dfrac{29}{-x}\le x\le\dfrac{-1}{2}+2+\dfrac{5}{2}\)
Bài 1: Tìm n thuộc Z để cho các phân số sau đồng thời có giá trị nguyên.
\(\dfrac{-12}{n}\) \(\dfrac{15}{n-2}\) \(\dfrac{8}{n+1}\)
Bài 2: Tìm x thuộc Z biết:
\(a,\dfrac{x-1}{9}=\dfrac{8}{3}\) \(b,\dfrac{-x}{4}=\dfrac{-9}{x}\) \(c,\dfrac{x}{4}=\dfrac{x}{x+1}\)
bài 1: tìm x bt:
a\(\dfrac{2}{3}x-\dfrac{1}{2}=\dfrac{1}{10}\)
b, \(5\dfrac{4}{7}:x=13\)
c, (2 và 4/5.x-50) :2/3= 51
d,\(\left(x+\dfrac{1}{2}\right).\left(\dfrac{2}{3}-2x\right)=0\)
e, \(\dfrac{2}{3}-\dfrac{1}{2}x=\dfrac{5}{12}\)
giúp mk nhs!!!!!!!!!!
Tìm số tự nhiên x
a) \(\dfrac{x}{2008}-\dfrac{1}{10}-\dfrac{1}{15}-\dfrac{1}{21}-....-\dfrac{1}{120}=\dfrac{5}{8}\)
b)\(\dfrac{1}{3.5}+\dfrac{1}{5.7}+\dfrac{1}{7.9}+....+\dfrac{1}{\left(2x+1\right).\left(2x+3\right)}=\dfrac{15}{93}\)
