Question

1 tìm x
\(\dfrac{3}{4}-\left(2x-\dfrac{2}{3}\right)=\dfrac{-5}{6}\)
\(1,5-\left(x+\dfrac{7}{2}\right)=2^7:2^5\)
\(-12\left(\dfrac{1}{2}-3x\right)^3-\sqrt{16}=\left|-46\right|\)

Answer 1

a. \(\dfrac{3}{4}-\left(2x-\dfrac{2}{3}\right)=\dfrac{-5}{6}\)

\(\Rightarrow2x-\dfrac{2}{3}=\dfrac{3}{4}-\dfrac{-5}{6}\)

\(\Rightarrow2x-\dfrac{2}{3}=\dfrac{19}{12}\)

\(\Rightarrow2x=\dfrac{19}{12}+\dfrac{2}{3}=\dfrac{9}{4}\)

\(\Rightarrow x=\dfrac{9}{4}:2=\dfrac{9}{8}\)

Vậy............

b. \(1,5-\left(x+\dfrac{7}{2}\right)=2^7:2^5\)

\(\Rightarrow1,5-\left(x+\dfrac{7}{2}\right)=2^2=4\)

\(\Rightarrow x+\dfrac{7}{2}=1,5-4=\dfrac{-5}{2}\)

\(\Rightarrow x=\dfrac{-5}{2}-\dfrac{7}{2}=-6\)

Vậy.............