đề mk ko vt lại nữa nhé mk làm tiếp luôn :
a, x3+9x2+27x+27 -x(x2-16)=27
<=> x3+3x2+27x +27-x3+16x=27
<=> 3x2+43x=0<=> x=0 hoặc x=-43/3
vậy phương trình đã cho có tập nghiệm .....
b,<=> (3x-2-3x-5)(3x-2+3x+5)=4
<=>-8(6x+3)=4<=> 6x+3=-\(\dfrac{1}{2}\)<=>x=\(\dfrac{-7}{12}\) Vậy x=...
câu c, tương tự câu b,
1 Tìm x
a,(2.x-5)2-(2.x-3)(2x+3)=5
b,(x+3)3-x(x+4)(x-4)=27
c,(3x-2)2-(3x+5)2=4
d, (3x+5)2-(x-3)2=0
1 Tìm x
a,(2.x-5)2-(2.x-3)(2x+3)=5
b,(x+3)3-x(x+4)(x-4)=27
c,(3x-2)2-(3x+5)2=4
d, (3x+5)2-(x-3)2=0
27x^3 - 27 x^2 +3x - 1
1/27 + x^3
x^3- 3x^2+3x-1
0,001-1000x^3
12/5 x^2y^2-9x^4 - 4/25y^4
a^2y^2+b^2x^2-2axby
100-(3x-y)^2
64x^2-(8a+b)^2
27x^3-a^3b^3
1, tìm x :
a) (x+2).(x+3)-(x-2).(x+5)=0
b) (2x+3).(x-4)+(x-5).(x-2)=(x-4).(3x-5)
c) (3x-5).(7-5x)-(5x+2).(2-3x)=3
d)(x-7).(x+7)-(x-4)2-x=10+3
e) (x+1/2)2-(x-1).(x+1)=2x-1
2, Thu gọn :
a) (x+5)2-(3-x)2-2(x-4).(x+4)
b)4(x-1)2+(2x+3)2-8(x-2)(x+2)
Tìm x biết
a,(x+4)^2-(x+1)(x-1)=16
b,(2x-1)^2-(x+3)-5(x-7)(x+7)=0
c,3(x-1)^2-3x(x-5)=1
d,6(x-2)^2+(5x-2)^2-4(3x-1)(5x-2)=0
e,(x-2)^3-x^2(x-6)=4
g,(x-1)(x^2+x+1)-x(x+2)(x-2)=5
h,(x-1)^3-(x+3)(x^2-3x+9)+3(x^2-4)=2
Tìm x:
a) (x - 2) (x2 + 2x + 7) + 2 (x2 - 4) - 5 (x - 2) = 0
b) 3x (x - 1) + (x - 1) = 0
c) 2 (x + 3) x2 - 3x = 0
d) 4x2 - 25 - (2x - 5)(2x + 7) = 0
e) x3 + 27(x + 3)(x - 9) = 0
Tìm x:
a) (2x + 3). (x - 4) + (x - 5). (x - 2) = (3x - 5). (x - 4)
b) (8 - 5x). (x + 2) + 4.(x - 2). (x + 1) + 2.(x - 2). (x + 2) = 0
c) (8x - 3). (3x + 2) - (4x - 7). (x + 4) = (2x + 1). (5x - 1) - 33
Tìm x biết
1.(x+3)2-(x+2).(x-2)=4x+17
2.(2x+1)2-(4x-1).(x-3)-15=0
3.(2x+3).(x-1)+(2x-3).(1-x)=0
4.2(5x-8)-3(4x-5)=4(3x-4)+11
5.(3x-1).(2x-7)-(1-3x).(6x-5)=0
1, tìm x :
a) (x+2).(x+3)-(x-2).(x+5)=0
b) (2x+3).(x-4)+(x-5).(x-2)=(x-4).(3x-5)
c) (3x-5).(7-5x)-(5x+2).(2-3x)=3
d)(x-7).(x+7)-(x-4)2-x=10+3
e) (x+1/2)2-(x-1).(x+1)=2x-1
2, Thu gọn :
a) (x+5)2-(3-x)2-2(x-4).(x+4)
b)4(x-1)2+(2x+3)2-8(x-2)(x+2)
