Question

1) Tìm x :

a) 4x² - 32x = 0

b) ( 2x - 1 )² + ( -x - 1 )² + 2( 1 + x )( 1 - 2x ) = 0

c) 1phần2x( 4x - 3 ) + 3x( -2phan3x + 1 ) = 1phần3

d) x² ​- 25 = 6x - 9 

 

Answer 1

a) 4x² - 32x = 0

=>4x(x-8)=0

=>4x=0 hoặc x-8=0

=>x=0 hoặc x=8

b) ( 2x - 1 )² + ( -x - 1 )² + 2( 1 + x )( 1 - 2x ) = 0

=>4x²-4x+1+x²+2x+1-4x²-2x+2=0

=>x²-4x+4=0

=>(x-2)²=0

=>x=2

c)đề khó hiểu

d)x² ​- 25 = 6x - 9 

=>x²-6x-16=0

=>​x²+2x-8x-16=0

=>x(x+2)-8(x+2)=0

=>(x-8)(x+2)=0

=>x=8 hoặc x=-2

 

 

Answer 2

  4x\(^2\)-32x=0

<=>4x(x-8)=0

<=>\(\hept{\left[\begin{array}{nghiempt}4x=0\\x-8=0\end{array}\right.}\)<=>\(\left[\begin{array}{nghiempt}x=0\\x=8\end{array}\right.\)

Vậy x= {;0;8)