Ta có 3n - 1 - 3n chia hết cho n
=> -1 chia hết cho n
=> n \(\in\) Ư( -1 ) = -1, 1
| n | -1 | 1 |
| 3n - 1 | -4 | 2 |
Ta có 2n + 1 - 2 ( n + 2 ) chia hết cho n - 2
=> 2n + 1 - 2n - 4 chia hết cho n - 2
=> -3 chia hết cho n - 2
=> n - 2 \(\in\) Ư (-3) = -3, 3
| n | -3 | 3 |
| 2n + 1 | -5 | 7 |
\(3n-1⋮n\)
\(3n⋮n\Rightarrow1⋮n\)
\(\Rightarrow n\in U\left(1\right)\)
\(U\left(1\right)=\left\{\pm1\right\}\)
\(\Rightarrow\left\{{}\begin{matrix}n=1\\n=-1\end{matrix}\right.\)
\(2n+1⋮n-2\)
\(\Rightarrow2n-4+5⋮n-2\)
\(2\left(n-2\right)+5⋮n-2\)
\(\Rightarrow5⋮n-2\)
\(\Rightarrow n-2\in U\left(5\right)\)
\(U\left(5\right)=\left\{\pm1;\pm5\right\}\)
\(\Rightarrow\left\{{}\begin{matrix}n-2=1\Rightarrow n=3\\n-2=-1\Rightarrow n=1\\n-2=5\Rightarrow n=7\\n-2=-5\Rightarrow n=-3\end{matrix}\right.\)
