1. a)\(2\&\sqrt{5}\)
\(2=\sqrt{4}\)
=> \(2< \sqrt{5}\)
b)\(5\&\sqrt{23}\)
\(5=\sqrt{25}\)
=> \(5>\sqrt{23}\)
c) \(\sqrt{23}+\sqrt{13}\&\sqrt{83}\)
\(\left(\sqrt{23}+\sqrt{13}\right)^2=36+2\sqrt{229}\)
\(\left(\sqrt{83}\right)^2=83\)
\(\Rightarrow36+2\sqrt{299}< 83\)
=> \(\sqrt{23}+\sqrt{13}< \sqrt{83}\)
2. a) \(\sqrt{x}=5;x\ge0\)
=> x = 25
b) \(3\sqrt{x}=6;x\ge0\)
=> x = 4
c) trùng
d) \(3-\sqrt{3+1}=1\)
\(3-\sqrt{3+1}=3-2=1\)
1)
a)\(2=\sqrt{4}< \sqrt{5}\)
b) \(5=\sqrt{25}>\sqrt{23}\)
c) \(\sqrt{83}>\sqrt{81}=9\)
\(\left\{{}\begin{matrix}\sqrt{23}< \sqrt{25}=5\\\sqrt{13}< \sqrt{16}=4\end{matrix}\right.\)
\(\sqrt{23}+\sqrt{13}< 4+5=9\)
Vậy \(\sqrt{23}+\sqrt{13}< \sqrt{83}\)
2) Ta có:
\(\sqrt{x}=5\Rightarrow x=25\)
\(3\sqrt{x}=6\Rightarrow\sqrt{x}=2\Rightarrow x=4\)
\(3-\sqrt{3+1}=1\)
Nên:
\(3-2=1\)(luôn đúng)