Sửa đề thành H2 nhé!
\(n_{SO_2}=x;n_{O_2}=y\\ V_{CH_4}=V_{O_2}\Rightarrow n_{CH_4}=n_{O_2}=y\)
Theo đề bài ta có:
\(d_{A/H}=\frac{M_A}{M_{H_2}}=16\Leftrightarrow M_A=16.2=32\)
\(\Rightarrow\sum_m=\overline{A}.\sum_n=32.\left(x+2y\right)\left(1\right)\)
\(\sum_V=22,4\left(x+2y\right)\left(l\right)\)
\(\sum_m=64x+32y+18y=64x+50y\left(2\right)\)
\(\left(1\right);\left(2\right)\Rightarrow32x+64y=64x+50y\\ \Leftrightarrow\frac{x}{y}=\frac{7}{16}\Rightarrow\left\{{}\begin{matrix}x=7\\y=16\end{matrix}\right.\)
\(\%V_{SO_2}=\frac{22,4x}{22,4\left(x+2y\right)}.100\%=\frac{x}{x+2y}.100\%=\frac{7}{7+16.2}.100\%=17,94\left(\%\right)\)
\(\%V_{O_2}=\%V_{CH_4}=\frac{22,4y}{22,4\left(x+2y\right)}.100\%=\frac{y}{x+2y}.100\%=\frac{16}{7+16.2}.100\%=41,03\left(\%\right)\)
\(\%m_{SO_2}=\frac{64x}{64x+50y}.100\%=\frac{64.7}{64.7+50.16}.100\%=35,9\left(\%\right)\)
\(\%m_{O_2}=\frac{32y}{64x+50y}.100\%=\frac{32.16}{64.7+50.16}.100\%=41,03\left(\%\right)\)
\(\%m_{SO_2}=\frac{18y}{64x+50y}.100\%=\frac{18.16}{64.7+50.16}.100\%=23,07\left(\%\right)\)
