a) Tổng số Nu của mỗi gen là: 360000 : 300 = 1200 (N)
Gen 1: \(\frac{A_1+T_1^{^{^{ }}}}{G_1+X_1^{ }}\)=\(\frac{2}{3}\) \(\Rightarrow\) \(\frac{2A_1}{2G_1}\) = \(\frac{2}{3}\) (vì A=T, G=X)
\(\Rightarrow\) \(\frac{A_1}{G_1}\) = \(\frac{2}{3}\) (1)
Ta có: A1 + T1 + G1 + X1 = 1200
\(\Leftrightarrow\) 2A1 +2G1 = 1200
\(\Rightarrow\) A1 + G1 = \(\frac{1200}{2}\) = 600 (2)
Từ (1) và (2) ta có: \(\left\{\begin{matrix}\frac{A_1}{G_1}=\frac{2}{3}\\A_1+G_1=600\end{matrix}\right.\) \(\Rightarrow\) \(\left\{\begin{matrix}A_1=240\\G_1=360\end{matrix}\right.\)
\(\Rightarrow\) T1 =A1 =240 (N)
\(\Rightarrow\) G1 =X1 = 360 (N)
Gen 2: \(\frac{G_2+X_2}{A_2+T_2}\) = \(\frac{5}{3}\) \(\Rightarrow\) \(\frac{2G_2}{2A_2}\) = \(\frac{5}{3}\) \(\Rightarrow\) \(\frac{G_2}{A_2}\) = \(\frac{5}{3}\) (3)
Ta có: A2 + T2 + G2 + X2 = 1200
\(\Rightarrow\) A2 + G2 = 600 (4)
Từ (3) và (4) ta có: \(\left\{\begin{matrix}\frac{G_2}{A_2}=\frac{5}{3}\\A_2+G_2=600\end{matrix}\right.\) \(\Rightarrow\) \(\left\{\begin{matrix}A_2=225\\G_2=375\end{matrix}\right.\)
\(\Rightarrow\) T2 = A2 = 225 (N)
\(\Rightarrow\) X2 = G2 = 375 (N)
b) Ta có: AADN = A1+ A2 = 240 + 225 = 465 (N)
TADN = AADN = 465 (N)
GADN = G1 + G2 = 360 + 375 = 735 (N)
XADN = GADN = 735 (N)
