\(1\dfrac{3}{4}.x+1\dfrac{1}{2}=-\dfrac{4}{5}\\ \Leftrightarrow\dfrac{7}{4}x+\dfrac{3}{2}=-\dfrac{4}{5}\\ \Leftrightarrow35x+30=-16\\ \Leftrightarrow35x=-16-30\\ \Leftrightarrow35x=-46\\ \Leftrightarrow x=-\dfrac{46}{35}\)
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\(1\dfrac{3}{4}x+1\dfrac{1}{2}=\dfrac{-4}{5}\)
\(\Leftrightarrow\dfrac{7}{4}x+\dfrac{3}{2}=\dfrac{-4}{5}\)
\(\Leftrightarrow\dfrac{7}{4}x=\dfrac{-4}{5}-\dfrac{3}{2}\)
\(\Leftrightarrow\dfrac{7}{4}x=\dfrac{-23}{10}\)
\(\Leftrightarrow x=\dfrac{-23}{10}:\dfrac{7}{4}\)
\(\Leftrightarrow x=\dfrac{-46}{35}\)