a.
\(Q=mc\left(t_2-t_1\right)=0,6\cdot460\cdot\left(100-20\right)=22080\left(J\right)\)
b.
Cân bằng nhiệt: \(Q_{thu}=Q_{toa}\)
\(\Leftrightarrow m\cdot4200\cdot\left(40-30\right)=0,6\cdot460\cdot\left(100-40\right)\)
\(\Leftrightarrow42000m=16560\)
\(\Leftrightarrow m\approx0,4\left(kg\right)\)
