Question

Answer 1

\(\Leftrightarrow\dfrac{1}{4}\left(2x-1\right)=\dfrac{5}{8}.\\ \Leftrightarrow2x-1=\dfrac{5}{2}.\\ \Leftrightarrow x=\dfrac{7}{4}.\)

Answer 2

\(\dfrac{5}{8}+\dfrac{1}{4}\left(2x-1\right)=\dfrac{5}{4}\\ \dfrac{1}{4}\left(2x-1\right)=\dfrac{5}{4}-\dfrac{5}{8}\\ \dfrac{1}{4}\left(2x-1\right)=\dfrac{5}{4}\\ 2x-1=\dfrac{5}{4}:\dfrac{1}{4}\\ 2x-1=5\\ 2x=6\\ x=3\)