Question

Answer 1

\(MCD:R1//R2\)

\(\Rightarrow R_{td}=\dfrac{R1\cdot R2}{R1+R2}=\dfrac{40\cdot60}{40+60}=24\Omega\)

Ta có: \(U=U1=U2=36V\Rightarrow\left[{}\begin{matrix}I=\dfrac{U}{R}=\dfrac{36}{24}=1,5A\\I1=\dfrac{U1}{R1}=\dfrac{36}{40}=0,9A\\I2=\dfrac{U2}{R2}=\dfrac{36}{60}=0,6A\end{matrix}\right.\)

\(\Rightarrow P=UI=36\cdot1,5=54\)(W)

Ta có: \(I_d=\dfrac{P_d}{U_d}=\dfrac{24}{12}=2A>I\left(2A>1,5\right)\Rightarrow\) đèn không sáng bình thường