Question

Answer 1

\(R_{nt}=R1+R2=\dfrac{U}{I}=\dfrac{24}{0,6}=40\Omega\left(1\right)\)

\(R_{ss}=\dfrac{R1\cdot R2}{R1+R2}=\dfrac{U'}{I'}=\dfrac{12}{1,6}=7,5A\)\(\Leftrightarrow\dfrac{1}{R1}+\dfrac{1}{R2}=\dfrac{1}{7,5}\left(2\right)\)

Thay (1) vào (2), ta có: \(R1\cdot R2=300\Omega\)

\(\left(1\right)\rightarrow R2=40-R1\)\(\Leftrightarrow R1\left(40-R1\right)=300\Leftrightarrow R1=30\Omega\)

\(\Rightarrow R2=10\Omega\)

Hoặc: \(\left[{}\begin{matrix}R1=10\Omega\\R2=30\Omega\end{matrix}\right.\)