Question

Answer 1

a.\(M=\dfrac{1}{3}\left(-6x^2y^2\right)^2.\left(\dfrac{1}{2}x^3y\right)=\dfrac{1}{3}\left(36x^4y^4\right).\left(\dfrac{1}{2}x^3y\right)=12x^4y^4.\dfrac{1}{2}x^3y=6x^7y^5\)

b.Thế \(x=1;y=-1\) vào M, ta được:

\(6x^7y^5=6.1^7.\left(-1\right)^5=6.1.-1=-6\)

Answer 2

`a)` `M = 1/3( -6x^2y^2 )^2 . ( 1/2x^3y )`

    `= ( (6^2 ) . 1/2 . 1/3 ) . ( x^4 . x^3 ) . ( y^4 . y )`

   `= 6x^7y^5`

`b)` Thay `x=1;y=-1` vào `M` ta có `:`

`M = 6.1^7 . ( -1 )^5 = -6` 

Answer 3