Question

Answer 1

a.Hiện tượng: copper (II) oxide tan dần, dd có màu xanh

\(2CH_3COOH+CuO\rightarrow\left(CH_3COO\right)_2Cu+H_2O\)

b.c.\(n_{CH_3COOH}=\dfrac{600.10\%}{60}=1mol\)

Theo pt:\(n_{\left(CH_3COO\right)_2Cu}=\dfrac{n_{CH_3COOH}}{2}=\dfrac{1}{2}=0,5mol\)
             \(n_{CuO\left(lý.thuyết\right)}=\dfrac{n_{CH_3COOH}}{2}=\dfrac{1}{2}=0,5mol\)

\(m_{\left(CH_3COO\right)_2Cu}=0,5.182=91g\)

\(m_{CuO\left(thực.tế\right)}=0,5.80+5=45g\)

\(n_{CuO\left(thực.tế\right)}=\dfrac{45}{80}=0,5625mol\)

\(H=\dfrac{0,5}{0,5625}.100=88,89\%\)

d.

\(2Al+6CH_3COOH\rightarrow2\left(CH_3COO\right)_3Al+3H_2\)

                  1                                                 0,5      ( mol )

\(V_{H_2}=0,5.22,4=11,2l\)