Question

Answer 1

Bài 8:

\(n_{H_2}=\dfrac{0,28}{22,4}=0,0125\left(mol\right)\)

PTHH: 2Na + 2H₂O ---> 2NaOH + H₂

          0,025<-----------------0,025<----0,0125

\(a,n_{Na}=0,025.23=0,575\left(g\right)\\ b,m_{NaOH}=0,025.40=1\left(g\right)\)

Câu 9:

PTHH: Zn + 2HCl ---> ZnCl₂ + H₂

           0,3<---0,6<---------------0,3

a, m_Zn = 0,3.65 = 19,5 (g)

b, m_HCl = 0,6.36,5 = 21,9

Answer 2

\(n_{H_2}=\dfrac{0,28}{22,4}=0,0125\left(mol\right)\\ pthh:2Na+2H_2O\rightarrow2NaOH+H_2\)
           0,025                 0,025        0,0125 
\(\Rightarrow m_{Na}=0,025.23=0,575\left(g\right)\\ m_{NaOH}=0,025.40=1\left(g\right)\)