Question

Answer 1

\(\lim\limits_{x\rightarrow2^+}f\left(x\right)=\lim\limits_{x\rightarrow2^+}\left(x^2+ax+1\right)=2a+5\)

\(\lim\limits_{x\rightarrow2^-}f\left(x\right)=\lim\limits_{x\rightarrow2^-}\left(2x^2-x+1\right)=7\)

Để hàm có giới hạn khi \(x\rightarrow2\) thì: \(2a+5=7\Rightarrow a=1\)