Question

Answer 1

\(a.pthh:Na_2CO_3+2HCl--->2NaCl+CO_2\uparrow+H_2O\)

b. Ta có: \(n_{Na_2CO_3}=\dfrac{10,6}{106}=0,1\left(mol\right)\)

Theo pt: \(n_{CO_2}=n_{Na_2CO_3}=0,1\left(mol\right)\)

\(\Rightarrow V_{CO_2}=0,1.22,4=2,24\left(lít\right)\)

c. Theo pt: \(n_{HCl}=2.n_{CO_2}=2.0,1=0,2\left(mol\right)\)

\(\Rightarrow m_{HCl}=0,2.36,5=7,3\left(g\right)\)