\(\lim\limits_{x\rightarrow-\infty}\dfrac{\sqrt{4x^2-7x+12}}{3\left|x\right|-17}=\lim\limits_{x\rightarrow-\infty}\dfrac{\left|x\right|\sqrt{4-\dfrac{7}{x}+\dfrac{12}{x^2}}}{3\left|x\right|-17}=\lim\limits_{x\rightarrow-\infty}\dfrac{\sqrt{4-\dfrac{7}{x}+\dfrac{12}{x^2}}}{3-\dfrac{17}{\left|x\right|}}\)
\(=\dfrac{\sqrt{4}}{3}=\dfrac{2}{3}\)



