Question

Answer 1

Giúp mình câu hỏi này với

Answer 2

\(\Leftrightarrow\dfrac{3\left(x-1\right)}{6}=\dfrac{2\left(x+2\right)}{6}\)

\(\Leftrightarrow3\left(x-1\right)=2\left(x+2\right)\)

\(\Leftrightarrow3x-3=2x+4\)

\(\Leftrightarrow x=7\)

Answer 3

\(\dfrac{3x-3}{6}=\dfrac{2x+4}{6}\)

3x-3=2x+4

3x-2x=4+3

x=7

 

Answer 4

\(\dfrac{x-1}{2}=\dfrac{x+2}{3}\)

\(\Leftrightarrow\)\(\dfrac{3\left(x-1\right)}{6}=\dfrac{2\left(x+2\right)}{6}\)

\(\Leftrightarrow\)  \(3\left(x-1\right)=2\left(x+2\right)\)
\(\Leftrightarrow\)  \(3x-3=2x+4\) 

\(\Leftrightarrow\)  \(3x-2x=4+3\)

\(\Leftrightarrow\)  \(x=7\)

Vậy: Phân thức có n_o là x = 7

Hoặc: S={7}

HT