Question

Answer 1

a: \(=\dfrac{-24}{42}+\dfrac{9}{42}-\dfrac{16}{42}=\dfrac{-31}{42}\)

b: \(=\dfrac{-7}{12}+\dfrac{8}{15}-\dfrac{17}{18}=\dfrac{-105}{180}+\dfrac{96}{180}-\dfrac{170}{180}=\dfrac{-179}{180}\)

c: \(=\dfrac{1}{4}-\dfrac{1}{2}-\dfrac{1}{3}=\dfrac{3}{12}-\dfrac{6}{12}-\dfrac{4}{12}=\dfrac{-7}{12}\)

d: \(=\dfrac{-11}{24}-\dfrac{13}{30}+\dfrac{25}{18}=\dfrac{-165}{360}-\dfrac{156}{360}+\dfrac{500}{360}=\dfrac{179}{360}\)