Lời giải:
Đặt $\frac{a+b}{3}=\frac{b+c}{4}=\frac{c+a}{5}=t$
$\Rightarrow a+b=3t; b+c=4t; c+a=5t$
$\Rightarrow a+b+c=(3t+4t+5t):2=6t$
$a=(a+b+c)-(b+c)=6t-4t=2t$
$b=(a+b+c)-(a+c)=6t-5t=t$
$c=(a+b+c)-(a+b)=6t-3t=3t$
$M=10a+b-7c+2021=10.2t+t-7.3t+2021=2021$
Đáp án D.
