\(n_{Cu}=0,2(mol)\\ n_{NO}=a(mol);n_{NO_2}=b(mol)\\ Cu\to Cu^{2+}+2e\\ 0,2..................0,4\\ N^{+5}+1e\to N^{+4}\\ .........b.....b\\ N^{+5}+3e\to N^{+2}\\ ........3a.....a\)
Bảo toàn e: \(3a+b=0,4(1)\)
\(d_{khí/H_2}=19\\ \Rightarrow \dfrac{30a+46b}{a+b}=2.19\\ \Rightarrow 30a+46b=38(a+b)\\ \Rightarrow 4a-4b=0\Rightarrow a=b(2)\\ (1)(2)\Rightarrow a=b=0,1(mol)\\ \Rightarrow V_{NO}=V_{NO_2}=0,1.22,4=2,24(l)\)
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