Question

Answer 1

\(\left|2x+\dfrac{1}{5}\right|=\dfrac{1}{2}\)

⇒ \(\left[{}\begin{matrix}2x+\dfrac{1}{5}=\dfrac{1}{2}\\2x+\dfrac{1}{5}=-\dfrac{1}{2}\end{matrix}\right.\)

⇒ \(\left[{}\begin{matrix}2x=\dfrac{3}{10}\\2x=-\dfrac{7}{10}\end{matrix}\right.\)

⇒ \(\left[{}\begin{matrix}x=\dfrac{3}{20}\\x=-\dfrac{7}{20}\end{matrix}\right.\)

Answer 2

\(\dfrac{6}{7}+\dfrac{1}{7}x+\dfrac{3}{14}\)

\(6.\dfrac{1}{7}+\dfrac{1}{7}.x=\dfrac{3}{14}\)

\(\dfrac{1}{7}\left(x+6\right)=\dfrac{3}{14}\)

\(x+6=\dfrac{3}{14}:\dfrac{1}{7}=\dfrac{3}{2}\)

\(x=\dfrac{3}{2}-6=-\dfrac{9}{2}\)