\(n_{Zn}=\dfrac{6,5}{65}=0,1\left(mol\right)\\ Zn+2HCl\rightarrow ZnCl_2+H_2\\ 0,1......0,2........0,1........0,1\left(mol\right)\\ a,V_{H_2\left(đktc\right)}=0,1.22,4=2,24\left(l\right)\\ b,C_{MddHCl}=\dfrac{0,2}{0,15}=\dfrac{4}{3}\left(M\right)\\ c,ZnCl_2+2AgNO_3\rightarrow Zn\left(NO_3\right)_2+2AgCl\\ n_{AgNO_3}=2.n_{ZnCl_2}=2.0,1=0,2\left(mol\right)\\ m_{ddAgNO_3}=\dfrac{0,2.170.100}{10}=340\left(g\right)\)
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