Question

Answer 1

a. Bạn tự vẽ sơ đồ mạch điện nhé!
\(\left\{{}\begin{matrix}R_{banla}=\dfrac{U_{banla}^2}{P_{banla}}=\dfrac{220^2}{1000}=48,4\Omega\\R_{den}=\dfrac{U_{den}^2}{P_{den}}=\dfrac{220^2}{100}=484\Omega\end{matrix}\right.\)

\(\Rightarrow R_{td}=\dfrac{R_{banla}\cdot R_{den}}{R_{banla}+R_{den}}=\dfrac{48,4\cdot484}{48,4+484}=44\Omega\)

b. \(I=I_{banla}+I_{den}=\left(\dfrac{220}{48,4}\right)+\left(\dfrac{220}{484}\right)=5A\)

\(\Rightarrow A=UIt=220\cdot5\cdot1=1100\)Wh = 1,1kWh = 3960000J