Bài 39:
\(\dfrac{x}{2}=\dfrac{y}{5};\dfrac{y}{4}=\dfrac{z}{3}\Leftrightarrow\dfrac{x}{8}=\dfrac{y}{20}=\dfrac{z}{15}\)
Áp dụng tc dtsbn:
\(\dfrac{x}{8}=\dfrac{y}{20}=\dfrac{z}{15}=\dfrac{x+y-z}{8+20-15}=\dfrac{39}{13}=3\\ \Leftrightarrow\left\{{}\begin{matrix}x=24\\y=60\\z=45\end{matrix}\right.\)

