Question

Answer 1

Câu 1.

\(Cu+2AgNO_3\rightarrow Cu\left(NO_3\right)_2+2Ag\)

x             2x                                   2x

Độ tăng khối lượng:

\(108\cdot2x-64x=152\Rightarrow x=1mol\)

\(C_M=\dfrac{1}{1}=1M\)

Answer 2

Bài 1:

PTHH: \(Cu+2AgNO_3\rightarrow Cu\left(NO_3\right)_2+2Ag\)

Gọi \(n_{Cu\left(p.ứ\right)}=a\left(mol\right)\) \(\Rightarrow n_{Ag}=2a\left(mol\right)\)

Ta có: \(m_{tăng}=15,2=108\cdot2a-64a\) \(\Rightarrow a=0,1\left(mol\right)\)

\(\Rightarrow C_{M_{AgNO_3}}=\dfrac{0,1\cdot2}{1}=0,2\left(M\right)\)