\(U_{MB}=U2=U3=14,4V\)(R2//R3)
\(\Rightarrow\left\{{}\begin{matrix}I2=U2:R2=14,4:10=1,44A\\I3=U3:R3=14,4:15=0,96A\end{matrix}\right.\)
Ta có: \(I_{AB}=I_{AM}=I_{MB}=1,44+0,96=2,4A\left(R1ntR23\right)\)
\(\Rightarrow I_1=2,4A\)
\(U_{AM}=U_{AB}-U_{MB}=24,4-14,4=10V\)
\(\Rightarrow U_1=10V\)
\(\Rightarrow R1=U1:I1=10:2,4=\dfrac{25}{6}\Omega\)



