Question

Answer 1

\(\dfrac{x}{5}=\dfrac{y}{4}=\dfrac{z}{3}=\dfrac{2y}{8}=\dfrac{3z}{9}=\dfrac{x+2y-3z}{5+8-9}=\dfrac{x-2y+3z}{5-8+9}=\dfrac{x+2y-3z}{4}=\dfrac{x-2y+3z}{6}\)

\(\Rightarrow\dfrac{x+2y-3z}{4}=\dfrac{x-2y+3z}{6}\)

\(\Rightarrow P=\dfrac{x+2y-3z}{x-2y+3z}=\dfrac{4}{6}=\dfrac{2}{3}\)