\(a,=\left(\dfrac{3}{4}\right)^2+\left(-\dfrac{1}{12}\right)^2=\dfrac{9}{16}+\dfrac{1}{144}=\dfrac{41}{72}\\ b,=3^4-5^2+2^6=81-25+64120\\ c,=4\cdot\dfrac{1}{16}+25\left(\dfrac{3}{4}:\dfrac{5}{4}\right)^3:\left(\dfrac{3}{2}\right)^3=\dfrac{1}{4}+25\left(\dfrac{3}{5}:\dfrac{3}{2}\right)^3\\ =\dfrac{1}{4}+25\cdot\left(\dfrac{2}{5}\right)^3=\dfrac{1}{4}+25\cdot\dfrac{8}{125}\\ =\dfrac{1}{4}+\dfrac{8}{5}=\dfrac{37}{20}\\ d,=8+3-1+\left(4\cdot2\right)-8=2+8=10\)
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