Question

Answer 1

a, \(\left[H^+\right]=0,001=10^{-3}\Rightarrow pH=3\)

Answer 2

b, \(\left[H^+\right]=2.0,005=0,01=10^{-2}\Rightarrow pH=2\)

Answer 3

c, \(\left[OH^-\right]=0,01=10^{-2}\Rightarrow\left[H^+\right]=10^{-12}\Rightarrow pH=12\)

Answer 4

d, \(\left[H^+\right]=0,05\Rightarrow pH=-log\left[H^+\right]\approx1,3\)