Question

Answer 1

\(a.n_{Al\left(NO_3\right)_3}=\dfrac{4,26}{213}=0,02\left(mol\right)\\ \left[Al^{3+}\right]=\left[Al\left(NO_3\right)_3\right]=\dfrac{0,02}{0,1}=0,2\left(M\right)\\ \left[NO^-_3\right]=3.0,2=0,6\left(M\right)\\ b.\left[Na^+\right]=0,1.1+0,02.2+0,3.1=0,44\left(M\right)\\ c.\left[H_2SO_4\right]=\dfrac{C\%.10D}{M}=\dfrac{15.10.1,1}{98}=\dfrac{75}{49}\left(M\right)\\ \Rightarrow\left[H^+\right]=\dfrac{75}{49}.2=\dfrac{150}{49}\left(M\right)\\ \left[SO^{2-}_4\right]=\dfrac{75}{49}\left(M\right)\)