\(n_{SO_3}=\dfrac{12}{22.4}=\dfrac{15}{28}\left(mol\right)\)
\(SO_3+H_2O\rightarrow H_2SO_4\)
\(\dfrac{15}{28}.............\dfrac{15}{28}\)
\(C_{M_{H_2SO_4}}=\dfrac{\dfrac{15}{28}}{0.2}=2.67\left(M\right)\)
\(b.\)
\(2NaOH+H_2SO_4\rightarrow Na_2SO_4+H_2O\)
\(\dfrac{15}{14}........\dfrac{15}{28}\)
\(m_{NaOH}=\dfrac{15}{14}\cdot40=42.85\left(g\right)\)
\(V_{dd_{NaOH}}=\dfrac{42.85}{20\%\cdot1.2}=178.5\left(ml\right)\)
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