\(n_{H_2SO_4}=n_{H_2O}=x\left(mol\right)\)
\(CT:A_2O_3\)
\(A_2O_3+3H_2SO_4\rightarrow A_2\left(SO_4\right)_3+3H_2O\)
Bảo toàn khối lượng :
\(10.2+98x=34.2+18x\)
\(\Rightarrow x=0.3\)
\(n_{Oxit}=\dfrac{0.3}{3}=0.1\left(mol\right)\)
\(M=\dfrac{10.2}{0.1}=102\left(đvc\right)\)
\(\Rightarrow2A+48=102\)
\(\Rightarrow A=27\)
\(CT:Al_2O_3\)
\(C_{M_{H_2SO_4}}=\dfrac{0.3}{0.2}=1.5\left(M\right)\)


